Twins rally past Reds with Brooks Lee’s 5 RBIs in decisive win
- The Minnesota Twins defeated the Cincinnati Reds 9-2 on Sunday, with Brooks Lee driving in five RBIs.
- Carlos Santana contributed significantly with three hits, including a two-run homer, as the Twins scored eight runs in the sixth and seventh innings.
- This victory allowed the Twins to maintain a 2.5-game lead over the Detroit Tigers for the last AL wild card spot.
On Sunday, the Minnesota Twins secured a decisive 9-2 victory over the Cincinnati Reds, marking their fourth win in the last twelve games. Rookie Brooks Lee was instrumental in the win, contributing five RBIs, while Carlos Santana had a standout performance with three hits, including a two-run homer. The Twins managed to rally after trailing 2-1, scoring eight runs in the sixth and seventh innings to avoid a three-game sweep. The game saw a turning point in the sixth inning when Santana hit a double, followed by an RBI double from Ryan Jeffers. Brooks Lee then delivered a two-run single that put the Twins ahead. In the seventh inning, Santana's two-run homer further extended the lead, and Lee capped off the scoring with a bases-loaded triple. Starting pitcher David Festa struggled, allowing two runs and three hits over 3 2/3 innings, continuing a trend of Minnesota starters not completing four innings. However, the bullpen stepped up, with Cole Sands and Jorge Alcala each throwing two scoreless innings, helping to maintain the lead. With this victory, the Twins improved their record to 79-70, holding a 2.5-game lead over the Detroit Tigers for the final AL wild card spot. The team is set to embark on a seven-game road trip, starting with a series against the Cleveland Guardians, as they aim to solidify their playoff position.